Help please!!!! Calculate the number of grams of Sulfur in 9.5 x 1022 molecules of H2SO4?

Question

chemistry homework..i can't seem to find the formula in the textbook.:(

Answer 1

For every molecule of H2SO4 there are 2 Hydrogen(H) atoms, 1 Sulfur(S) atom, and 4 Oxygen(O) atoms. So if there are 9.5 x 10^22 molecules of H2SO4 then are are also that number of sulfur molecules present.

To find how many grams 9.5 x 10^22 molecules weighs, use Avogadro's number. Dividing by Avogadro's number will tell you how many moles of Sulfur you have, and from that you can use the atomic mass of Sulfur to determine how many grams there are:

Avogradro's number = 6.02 x 10^23

(9.5 x 10^22) / (6.02 x 10^23) = 0.158 moles

Atomic mass of Sulfur = 32.065 g/mol

Multiply this by the number of moles of Sulfur you have to obtain the number of grams of Sulfur:

32.065 * 0.158 = 5.067 g

I hope this helps!

Answer 2

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Answer 3

Nomber of moles

9.5*1022/6.02 10^23 =1.613 10^(-20) moles of H2SO4

each mole of the acid has 1 atom sulfur weight 32 g

so mass of sulfur = 1.613*32 * 10^(-20 )= 5.16 10^(-19) g

Answer 4

divide by Avagadro's constant to get the number of moles of H2SO4 then multiply by the molecular weight of sulphur. And there's your answer.