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4 answers

(x + i)(x - i)(x - 3 + i)(x - 3 - i) = 0

(x^2 - i^2)[(x - 3)^2 - i^2] = 0

(x^2 + 1)(x^2 - 6x + 9 + 1) = 0

x^4 - 6x^3 + 10x^2 + x^2 - 6x + 10 = 0

x^4 - 6x^3 + 11x^2 - 6x + 10 = 0 (Answer)

2006-11-21 05:35:34 · answer #1 · answered by bpiguy 7 · 0 0

A polynomial of degree 3 signifies that the optimal exponent of x will be 3. because you comprehend what the zeros are, you could make sure what the equations are: x - 4 x + 7 x f(x) = (x - 4)(x + 7)x in case you placed those equivalent to 0, you receives your solutions.

2016-11-29 08:17:14 · answer #2 · answered by ? 4 · 0 0

If it has complex coefficients, there is an infinity of answers.

If they are real, it is a basic mathematical theorem that the complex roots come in conjugate pairs, so -i and (3 - i) are the other two roots. The polynomial is k(x^2 + 1)(x^2 - 6x + 10) for any k.

2006-11-21 02:21:47 · answer #3 · answered by Anonymous · 1 0

Do u know the answer?

2006-11-21 02:17:23 · answer #4 · answered by Wael 3 · 0 0

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