what mass of NaOH is required to react exactly with 25.0 mL of 2.7 M H2SO4?

Answer 1

Step one: find the moles of H2SO4. (2.7 moles per liter)*0.025 liters.

Step two: multiply by two because the reaction is
2NaOH + H2SO4 ----> 2H2O + Na2SO4 and so you need two NaOH molecules per molecule of H2SO4.

Step three: multiply by the molecular mass of NaOH.

That will get you the answer.

Answer 2

H2SO4 + 2(NaOH) ---> Na2SO4 + 2(H2O) no. of 6fd3bfdf2abc80de266e1f7ab88733ol6fd3bfdf2abc80de266e1f7ab88733s of H2SO4 M = n / L one million.0 M = n / 0.0.5 L n = 0.0.5 0.0.5 6fd3bfdf2abc80de266e1f7ab88733ol H2SO4 (2 6fd3bfdf2abc80de266e1f7ab88733ol NaOH / one million 6fd3bfdf2abc80de266e1f7ab88733ol H2SO4) = 0.05 6fd3bfdf2abc80de266e1f7ab88733ol NaOH gra6fd3bfdf2abc80de266e1f7ab88733s of NaOH 0.05 6fd3bfdf2abc80de266e1f7ab88733ol NaOH ( 39.ninety 9 g.NaOH / one million 6fd3bfdf2abc80de266e1f7ab88733ol NaOH ) = one million.ninety 9 or 2 g.NaOH [[6fd3bfdf2abc80de266e1f7ab887336fd3bfdf2abc80de266e1f7ab887336fd3bfdf2abc80de266e1f7ab887336fd3bfdf2abc80de266e1f7ab887336fd3bfdf2abc80de266e1f7ab887336fd3bfdf2abc80de266e1f7ab887336fd3bfdf2abc80de266e1f7ab887336fd3bfdf2abc80de266e1f7ab887336fd3bfdf2abc80de266e1f7ab88733]]

Answer 3

2 NaOH +H2SO4 = Na2SO4 + 2 H2O

So in moles of NaOH you need twice that of H2SO4

The moles of H2SO4 is 2.7 *25/1000 =0.0675

The moles of NaOH = 0.135moles

The molar weight of NaOH = 23+16+1 = 40g

and the mass of NaOH required = 0.135*40 = 5.4 G