well it didn't include all of the question so...
How much heat (in calories) must be applied to a 100 ml beaker filled with boiling water in order to vaporize the water?
2006-11-21 01:31:01 · 4 answers · asked by karyn823 1 in Science & Mathematics ➔ Chemistry
100 ml of water is 100 gms,
540 calories needed per gm of water turned to steam, so
54,000 calories will convert your 100 ml of boiling water into steam.
2006-11-21 01:43:35 · answer #1 · answered by Radagast97 6 · 2⤊ 1⤋
It takes 583 small energy to vaporize one gram of water at l00 degrees C to water vapor at l00 degrees C, And l00 ml of water weighs l00 grams. so 583 cal/gm circumstances l00 gms water = 58300 energy, or fifty 8.3 Kcal
2016-11-29 08:16:28 · answer #2 · answered by ? 4 · 1⤊ 0⤋
Q = m*c*(T2 - T1)
find the initial temp of the water and solve
2006-11-21 01:43:48 · answer #3 · answered by Charu Chandra Goel 5 · 0⤊ 1⤋
436degrees
2006-11-21 01:38:04 · answer #4 · answered by Anonymous · 0⤊ 2⤋