find the sum of interior angles of a ploygon with 30sides.
thanks
2006-11-21 01:12:36 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The sum of internal angles is (number of sides - 2) x 180 degrees
(30-2) = 28
28 x 180 = 5040 degrees
2006-11-21 01:14:52 · answer #1 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
If we represent the number of sides of a polygon as n, then the number of triangles you can form is (n-2). Since each triangle contains 1800, that gives us the formula:
Sum of Interior Angles = 180*(n-2) .
So, for a ploygon with 30sides
Sum of Interior Angles = 180*(30-2)
= 180*(28)
= 5040
I hope that is clear. All the best.
2006-11-21 01:30:02 · answer #2 · answered by Paritosh Vasava 3 · 0⤊ 0⤋
The formula for the sum of interior angles of a polygon is 180(n-2).
Where 'n' is the number of sides of the polygon.
Here, n = 30
Sum of angles = 180(n-2)
= 180(30 - 2)
= 180*28
= 5040 degrees
2006-11-21 02:12:37 · answer #3 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 1⤋
The sum of the interior angles of any polygon is given by
(n - 2) 180
Here n = 30
==> (30 - 2) 180 = 5040 degrees
2006-11-21 01:18:32 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Sum = 180(n-2) where n is number of sides
Sum = 180 (30-2)=180*28= 5040 degrees
2006-11-21 01:21:04 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
180(n-2) is the formula for interior angles. n being the number of sides in the polygon.
2006-11-21 01:16:48 · answer #6 · answered by Anonymous · 0⤊ 0⤋