Assuming that a small swimming pool contains 5000 liters of water. In order to prevent the growth of algae and sanitized the water, the pool maintenace used in 1.5ppm of chlorine per weekly application. How much amount of chlorine is needed monthly?
2006-11-21 00:17:57 · 4 answers · asked by killer 1 in Science & Mathematics ➔ Chemistry
Concentration equals mass/volume, or volume/volume, or mass/mass. In this case, we'll work with volume/volume.
1.5 ppm Cl per week is 6.0 ppm per month. This translates to 6.0 x 10^-6 L of Cl per L of pool water per month. The volume of Cl needed is then:
(6.0 x 10-6 L of Cl/L pool water)(5000 L pool water) = 3.0 x 10-2 L of Chlorine per month or 30 mL.
This assumes the problem does not expect you to calculate the equivalent mass of a particular product you would need to give that much available chlorine.
2006-11-21 00:33:50 · answer #1 · answered by rb42redsuns 6 · 0⤊ 0⤋
ppm means parts per million. Which means 1 milligram for each 1 kilogram. Assuming 1 litre of water weighs 1 kilogram 5000 milligram means 5 grams of chlorine will be sufficient.
2006-11-21 08:30:54 · answer #2 · answered by yogen p 2 · 0⤊ 0⤋
1.5 ppm means 1.5 mg per liter. To treat 5000 liters 7500 mg is needed which is 7.5 grams. That is the amount needed per week. Multiply by 4 to get 30 grams needed per month.
2006-11-21 10:04:51 · answer #3 · answered by xox_bass_player_xox 6 · 0⤊ 0⤋
5.5 L Chlorine
2006-11-21 08:21:14 · answer #4 · answered by Santhosh S 5 · 0⤊ 0⤋