Please can you tell me the length of the third side? Thank you.
2006-11-20 20:14:11 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Other - Science
The answer to your homework question is 5.62
2006-11-20 20:24:52 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Let the 17 degree angle be angle A and the side opposite be side a.
Let the other two angles be angles B and C, and the sides opposite these angles be b and c respectively.
Since b = c = 19 mm the triangle is an isosceles triangle. Angle B = angle C = (180 - 17)/2 = 81.5 degrees. This uses sum of the angles of a triangle = 180 degrees.
Now use the sine rule a/sin A = b/sin B = c/sin C
a/sin 17 = 19/sin 81.5
a = 19/sin 81.5 x sin 17
a = 5.616 mm
Answer: 5.62 mm (3 sf)
Also, since the triangle is isosceles there is no ambiguous case to consider. (Hope you know what this means)
2006-11-21 04:33:34 · answer #2 · answered by RATTY 7 · 0⤊ 0⤋
The other two angles will each be (180-17)/2 = 81.5 degrees.
x/sin17 = 19/sin81.5
x = 19sin17/sin81.5 = 5.62mm
2006-11-21 04:21:10 · answer #3 · answered by epbr123 5 · 0⤊ 0⤋
5.61676mm, the angles between this side and the other 2 sides are both 81.5 degrees.
2006-11-21 04:16:50 · answer #4 · answered by k² 6 · 0⤊ 1⤋
c^2 = a^2 +b^2 - 2abcos(θ)
c^2 = 361 + 361 - 2*361*cos(17)
c^2 = 2*361(1-cos(17))
c^2 = 31.548
c = 5.6168 mm
2006-11-21 05:28:29 · answer #5 · answered by Helmut 7 · 1⤊ 0⤋