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1. Consider two steel rods, A and B. B has three times the area and twice the length of A, so Young's modulus for B will be what factor times Young's modulus for A?

a. 3.0
b. 0.5
c. 1.0


2. An object has weight W on Earth. It is transported to the surface of Planet X which has 4 times the mass and 3 times the radius of Earth. What does the object weigh on Planet X?

a. (2/3) W
b. (9/5) W
c. (4/9) W
d. (1/9) W

Thanks a lot in advance guys!

2006-11-20 19:26:49 · 6 answers · asked by Anonymous in Science & Mathematics Physics

I did the algebra, and got the answers wrong. So I'm not clear on how to solve them because I figured my way was the correct way while doing these for homework.

2006-11-20 19:31:43 · update #1

6 answers

Youngs modulus = [F/A]/[∆L/L]; The modulus is a property of the material and does not depend on its dimensions, However, the modulus is used to find the total change in length (∆L) that comes from the pressure (stress) applied (F/A).

The weight will increase propotionately to the mass ratio and inversely proportional to the square of the distance (in this case the distance from the center of the planet, the radius). This is from Newton's Law, F = G*m1*m2/r^2 So that factor would be 4/9

2006-11-20 19:43:32 · answer #1 · answered by gp4rts 7 · 0 0

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2016-10-17 07:52:12 · answer #2 · answered by binnu 4 · 0 0

Young's Modulus = Y = Fl/eA
or if Force and e (extension) are taken as constants then Y = l/Aplugging in the data for YA and YB and taking ratios we get the answer
YB = 2/3YA







Let Me = the mass of the earth
g1 = the gravitational accelleration
Re = the radius of the earth
G = the universal gravitational constant
Mx = the mass of planet X
Rx = the radius of planet X
g2 = the accelleration due to gravity on the planet X

We can use the general formula with appropriate subscripts
g = GM/R^2

For Earth:
g1 = GMe/Re^2..........................................(1)

For Planet X:

g2 = GMx/Rx^2............................................(2)

Dividing 2 by 1, and knowing that Mx = 4Me, and Rx =3Re
we get the answer as (c) That is 4/9W

2006-11-20 21:08:55 · answer #3 · answered by quark_sa 2 · 0 0

for the first question....young's modulus is a material property so it does not depends on lenth,area.etc..but it only depends on the
nature of material..and varies from one material to another..here
both r steel bars so youngs modulus of B issame as that of A.
and coming to the second question it can b answered using newtons formulaF=G *m1*m2/ r^2..

2006-11-20 20:50:03 · answer #4 · answered by hiris(Hi..RiSK) 1 · 0 1

You said "conceptual physics" - this is just not bothering to do the algebra!

2006-11-20 19:29:17 · answer #5 · answered by lozatron 3 · 0 2

question 1 don't quite understand, i think is a
question 2 is b

2006-11-20 19:35:38 · answer #6 · answered by Koh Kian S 2 · 0 2

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