ow many grams of H2O are produced from the complete reaction of 68.12 g of NH3 ?

Question

For the reaction


NH3 + O2 → NO + H2O

Answer 1

90.12g of H2O are produced. you have to first convert to molar mass, then use the mole ratio of the balanced equation for NH3 and H20, then use molar mass again.

Answer 2

First you have to balance the reaction equation

NH3 + 5/4 O2 -> NO + 3/2 H2O

Okay so the multipliers are not integers. Just multiply all numbers by 4. However this form is more usefull for your problem.

Then the atomic weight of NH3 is 17. So there are 17 grams per mole. So now we know there are 68.12/17 = 4 Moles of NH3 , therefore there are 6 Moles of H2O produced. Since the atomic weight of H2O is 18, there are 6 * 18 = 108 grams of H2O produced.

Answer 3

First responder has a stable element. yet i can nevertheless define the ideas-set to the respond. The protocol for all issues of this style is often the comparable: first see if the reaction is balanced (it extremely is no longer), and in spite of if it extremely is no longer, restoration it. next compute the molecular weights of the important species (right here, H2O, and in spite of it extremely is that weighs sixty 8.12 grams). Then compute the form of moles of reactant, which provides you with the form of moles of product, and multiply that by utilising the suitable molecular weight to end the job.

Answer 4

about 108g