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An expandable cylinder has its top connected to a spring with force constant 2.00 103 N/m. (See Fig. P10.58.) The cylinder is filled with 4.50 L of gas with the spring relaxed at a pressure of 1.00 atm and a temperature of 20.0°C.

Here is the link to the figure:

http://i136.photobucket.com/albums/q200/physics2006/physics2.gif

2006-11-20 17:31:19 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

ANd the questions are:

a) If the lid has a cross-sectional area of 0.0100 m2 and negligible mass, how high will the lid rise when the temperature is raised to T = 260°C?

cm

(b) What is the pressure of the gas at 260°C?

Pa

2006-11-20 17:59:04 · update #1

3 answers

Use the fact that PV/T = a constant, we find the constant by pluging in the values we have, T = 20C, but we must convert that to K first so 20C = (273 + 20) = 293K. And 1 atm should be converted to physicall units of Nt/m^2 for an easier solution. 1 Atm = 101325 Nt/m^2. So our constant is (101325)(4.5)/293 = 1.336 x 10^7 so now you have one equation as

PV/T = 1.336 x 10^7 setting T = 260C or 533K gives
1) PV = 7.121 x 10^10

The next equation that we need is the force on the cylinder end given the pressure, which would be

2) .01P = F

The spring will stretch a distance 3) d = F / (2.00 x 10^3)

The volume changes by 4) V = 4.5 + d * .010

This gives you 4 equations which you can now solve to find the solution for V, d, P and F

2006-11-20 18:35:44 · answer #1 · answered by rscanner 6 · 0 0

this is probably physics or chemistry...not math

2006-11-21 01:42:10 · answer #2 · answered by craminator 3 · 0 0

what is the question

2006-11-21 01:40:26 · answer #3 · answered by Anonymous · 0 0

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