What is the Maclaurin series for cosh (2)?

Answer 1

..... ..... ... ∞
cosh(2) = ∑(1/2n!)2^(2n) =
..... ......... n = 1

∑[4/2 + 16/4! + 64/6! + 256/8! + ..... + (2^(2n))/(2n!)]