help with this math question?

10 ⤊

Factor the trinomial y^2 + 2y -8
^2= 2nd power and how would I write that?

2006-11-20 16:22:23 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

y^2+2y-8
(y+4)(y-2)

2006-11-20 16:46:55 · answer #1 · answered by yupchagee 7 · 10⤊ 0⤋

y^2 + 2y - 8
y^2 + 2y -8 = 0
y^2 +4 y - 2y - 8 = 0
y (y + 4) - 2(y + 4) = 0
(y- 2) (y+ 4) = 0
y- 2 = 0 , y = 2
OR
y+ 4 = 0, y = -4

2006-11-21 01:17:00 · answer #2 · answered by thonjela 1 · 0⤊ 0⤋

y^2 + 2y -8
= y^2 + 4y - 2y - 8
= y(y + 4) -2(y + 4)
= (y - 2)(y + 4)

2006-11-21 23:36:10 · answer #3 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 1⤋

factor

(y+4)(y-2)=0
y = -4.2

2006-11-21 00:25:01 · answer #4 · answered by spoonish18 2 · 0⤊ 0⤋

do your homework

2006-11-21 00:25:49 · answer #5 · answered by fleisch 4 · 0⤊ 0⤋