Solve the equation -2x^2 + 6x -3 = 0.
^ = 2nd power
took me a while to figure this out can you?
2006-11-20 15:48:34 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
-2x^2+6x-3=0
=->2(x^2-3x+3/2)=0
=>2(x^2-2x.3/2+3^2/2^2)-3/4=0
=2(x+3/2)^2-(sqrt3/2)^2=0
=>-2(x+3/2+sqrt3/2)(x+3/2-sqrt3/2)=0
Therefore,x=-3/2-sqrt3/2 or -3/2+sqrt3/2
2006-11-21 03:18:02 · answer #1 · answered by alpha 7 · 0⤊ 1⤋
you complete the square. x^2+3x-3/2=0
x^2+3x=3/2
x^2+3x+9/4=15/4
(x+3/2)^2=15/4
x+3/2=square root of 15/2
x=((sqrt 15)-3)/2
2006-11-20 23:54:51 · answer #2 · answered by mistert0312 2 · 1⤊ 0⤋
X = 3/2 +- (sqrt(3))/2
Just complete the square or use the quadratic formula
2006-11-21 11:00:33 · answer #3 · answered by Arkane Steelblade 4 · 0⤊ 1⤋
use that formula thing A +/- SQRT4xA*B/ AC or sumpthing like that
2006-11-20 23:54:29 · answer #4 · answered by mike c 5 · 0⤊ 2⤋
i tried and failed
2006-11-20 23:58:02 · answer #5 · answered by queen_hanna 2 · 0⤊ 2⤋