How do I solve this system by using the method of substitution?

Question

y = x - 1
y = (x - 1)^3



^3 means third power.

Answer 1

y = x - 1
y = (x - 1)^3
substitute x-1 gor y
x-1=(x-1)^3 divide by x-1
1=(x-1)^2
1=x^2-2x+1 subtract 1
x^2-2x=0
x(x-2)=0
x=0
x-2=0
x=2

roots are
x=0,2

Answer 2

y = x - 1
y = (x - 1)^3
Obviously,
(x - 1)^3 = x - 1
This is only possible when x-1 = 0, 1 or -1
x can be 0, 1 or 2
x = 0,1,2
So y can be 0, 1 or -1
y = 0,1, -1
No substitution method is needed

Answer 3

It seems to me this is a nonsense problem, because the first y equals (x-1), while the second one equals (x-1)(x-1)(x-1). So if you substitute the first value of y into the second expression, you're saying that (x-1) = (x-1)(x-1)(x-1). Doesn't seem right to me...