Simplify radical (12) – 4(radical 27) + 2(radical 75)
Simplify radical (sqrt 12) – 4(sqrt 27) + 2(sqrt 75)
2006-11-20 15:32:29 · 7 answers · asked by thomasgraham880 1 in Science & Mathematics ➔ Mathematics
√12 -4√27 + 2√75
= √4√3 - 4√9√3 + 2√25√3
= 2√3 - 4(3)√3 + 2(5)√3
= 2√3 - 12√3 + 10√3
= 0
2006-11-20 15:36:42 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Sqrt(12) = 2 * Sqrt(3)
- 4 * Sqrt(27) = - 4 * 3 * Sqrt(3)
+ 2 * Sqrt(75) = + 2 * 5 * Sqrt(3)
Add them up and you get (2 - 12 + 10)*Sqrt(3) = 0
2006-11-20 15:38:20 · answer #2 · answered by Anonymous · 0⤊ 0⤋
sqrt(12) - 4sqrt(27) + 2sqrt(75)
sqrt(4 * 3) - 4sqrt(9 * 3) + 2sqrt(25 * 3)
2sqrt(3) - (4 * 3)sqrt(3) + (2 * 5)sqrt(3)
2sqrt(3) - 12sqrt(3) + 10sqrt(3)
(2 - 12 + 10)sqrt(3)
(-10 + 10)sqrt(3)
0sqrt(3)
ANS : 0
2006-11-20 16:14:06 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
√12-4√27+2√75
2√3-4*3√3+10√3
(2-12+10)√3
0
2006-11-20 15:37:11 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
sqrt(12) - 4sqrt(27) +2sqrt(75)
= sqrt (4*3) -4 sqrt(9*3) + 2sqrt(25*5)
=2sqrt(3) - 12sqrt(3) + 10sqrt(5)
=-10sqrt(3) + 10sqrt(5)
=10(sqrt(5)-sqrt(3))
2006-11-20 15:41:51 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
12^.5=(4*3)^.5=2(3^.5)
4(27^.5)=4(9*3)^.5=12(3^.5)
2(75^.5)=2(25*3)^.5=10(3^.5)
2(3^.5)-12(3^.5)+10(3^.5)=0
:-)
2006-11-20 15:38:54 · answer #6 · answered by Anonymous · 0⤊ 0⤋
221155LLOO2233++
2016-05-22 04:02:22 · answer #7 · answered by Anonymous · 0⤊ 0⤋