2006-11-20 15:28:57 · 5 answers · asked by sarah 2 in Science & Mathematics ➔ Mathematics
Let y = sin x.
2y = 4y^2
4y^2 - 2y = 0
y(4y - 2) = 0
y = 0 or 4y - 2 =0
y = 0 or 1/2.
So sin(x) = 0 or 1/2. In degrees, using the range -90 to 90, this means that x is either 30 degrees or 90 degrees.
2006-11-20 15:33:10 · answer #1 · answered by Texas Cowgirl 3 · 0⤊ 0⤋
x = 0
x= 1/2
2006-11-20 23:55:22 · answer #2 · answered by analyn 3 · 0⤊ 0⤋
knowing basic sin values,
2sin x = 1
sin x =1/2
x=pi/6
thus 2 (sin(pi/4
2006-11-20 15:39:37 · answer #3 · answered by spoonish18 2 · 0⤊ 0⤋
4sin^2 x -2sin x=0
2sin x(2sin x-1)=0
sin x=0
x=nπ where n is any integer
2sin x-1=0
2sin x=1
sin x=1/2
x=nπ +π/6 where n is any even integer
x=mπ-π/6 where m is any odd integer
2006-11-20 15:35:32 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
2sin(x) = 4sin(x)^2
4sin(x)^2 - 2sin(x) = 0
(2sin(x))(2sin(x) - 1) = 0
2sin(x) - 1 = 0
2sin(x) = 1
sin(x) = (1/2)
x = 30° or 150°
2006-11-20 16:16:17 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋