Findind the length of a hypotenuse of each triangle.?

Question

ugh i hate math, but my teacher provided me with 4 right triangles 1 of them is a half of a square i just cant find the numbers of them i dont know how! cuz there was no number included with them. the next was like 1 hole square and half a 1 and another half of 1, HELP!

Answer 1

First of all, punctuation is your best friend. As in general spelling and good grammar.

What the heck do you mean by half of one?

And there must be some numbers somewhere otherwise the question is impossible to complete. What exactly do you see printed on your page?

Help us help you.

But most of all, pay attention in class. Ask your teacher when you don't understand something. It works wonders.

Answer 2

If the first right triangle was was formed by two sides of a square and the diagonal of the square, then the diagonal is the hypotenuse of the two triangles formed and is equal to the side multiplied by the square root of 2.

Now its hard to tell from your description, but it sounds like your teacher put another right triangle on the top of the square and another on the right side of the square. If so, this made a large right triangle with legs each = 2. So the hypotenuse of this triangle would be 2 times the side times the square root of 2.

Best I could do from info given.

Answer 3

I'm afraid your question doesn't make a lot of sense. In order to find the length of the hypotenuse of a triangle, you need to know either the length of both legs, or the length of one leg and the measure of one angle (aside from the right angle). If the right triangle is half of a square, then the two legs have equal length and both acute angles are 45 degrees. In that case, if the leg has length a, the hypotenuse has length a*sqrt(2), which you can find by using the Pythagorean theorem.

Answer 4

The general formula for finding the hipotanus is
a^2 = b^2 + c^2

First question:
assume the length of b and c are 1
so,
a^2= 1^2+1^2
= 2
a = the square root of 2


Second question
a^2 = (1/2)^2 +(1/2)^2
=(1/4) + (1/4)
=(1/2)
a = the square root of (1/2)

Answer 5

Non Isosceles Right Triangles(the ones that aren't half a square)

a^2 + b^2 = c^2

a and b are the legs
c is the hypothenuse

Isosceles Right Triangle
a^2 + b^2 = c^2
a = b
a^2 + a^2 = c^2
2a^2 = c^2

Answer 6

for the reason that's an isoceles desirable triangle, the legs are equivalent, and as a result Pythagorea's theorem a^2 + b^2 = c^2 could truly be a^2 + a^2 = 2a^2 = c^2. all of us be attentive to c = 80 one, as a result 2 a^2 = 80 one ^2 2 a^2 = 6561 a^2 = 6561 / 2 = 3280.5 a = sqrt (3280.5) = fifty seven.27 each and each leg could degree approx fifty seven.27

Answer 7

h^2=a^2+b^2
where
h is the hypotenuse
a & b are the 2 legs.

Answer 8

You need to be more specific.