how do you find csc(3pi/4) i cant do it T.T forgot how
2006-11-20 13:53:53 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
csc = 1/sin; sin(3π/4) = √2/2, so 1/(√2/2) = 2/√2 = √2
2006-11-20 13:57:23 · answer #1 · answered by gp4rts 7 · 1⤊ 0⤋
The radian measure (3pi/4) corresponds to (-sq rt.2/2, sq rt.2/2)
csc is 1/sin so the answer is (1/(sq rt.2)/ 2)
2006-11-20 13:56:58 · answer #2 · answered by MateoFalcone 4 · 1⤊ 0⤋
csc(3π/4) = 1 / sin(3π/4)
There is a formula that says : sin(A) = sin(π - A),
so, sin(3π/4) = sin(π - 3π/4) = sin(π/4).
Or in degrees, sin(135º) = sin(180º - 135º) = sin(45º).
The value of sin(45º) is calculated from the right-angled
isosceles triangle with legs of length 1 and hypotenuse
equal to sqrt(2).
So, sin(45º) = sin(π/4) = 1 / sqrt(2).
Now we have :
csc(3π/4) = 1 / sin(π/4) = 1 / [1 / sqrt(2)] = sqrt(2)
2006-11-21 00:25:35 · answer #3 · answered by falzoon 7 · 0⤊ 0⤋
csc=1/sin so
1/sin (3π/4)
sin 3π/4=√2 /2
csc (3π/4)=1/(√2 /2)=2/√2=2√2 /2=√2
csc(3π/4)=√2
2006-11-20 16:18:18 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
square root of 2
2006-11-20 23:51:29 · answer #5 · answered by analyn 3 · 0⤊ 0⤋
Did you look behind the refridgerator? Sometimes when you can't find things that is where they are.
2006-11-20 14:01:51 · answer #6 · answered by doggiebike 5 · 0⤊ 0⤋