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Lim (x+ x^2 + x^3 +... + x^n - n)/x-1 when x ---> 1 (tell more!)
Lim ((x^3)*Sin(1/x))/(1-cos(x)) when x ---> 0
Lim xtan(x) - (p/2)*Sec(x) when x ---> p/2
Lim (Sin^4(x))/ (4 - Cos(1-cos(x))) when x ---> 0
Lim (1-(x^2))/sin(px) when x --- > 1

2006-11-20 13:47:58 · 4 answers · asked by Arman Hassanpour 1 in Science & Mathematics Mathematics

4 answers

Use l'Hospital's Rule when dealing with 0/0 or intfy/infty: in such cases,

lim (f(x)/g(x)) = lim (f'(x)/g'(x)) if the latter exists (you may have to repeat this step using the second derivatives f''/g'').

In your first example, as x --> 1,

lim (x+ x^2 + x^3 +... + x^n - n)/(x-1)
= lim (1+ 2x + 3x^2 +... + nx^(n-1) )/1
= 1+ 2 + 3 +... + n = n(n+1)/2.

2006-11-20 13:53:51 · answer #1 · answered by Anonymous · 0 0

Lim (x+ x^2 + x^3 +... + x^n - n)/x-1 when x ---> 1 (tell more!)

Suppose n is 4 then (x^4 + x^3 + x^2 + x - 4)/(x-1)
becomes x^3 + 2x^2 + 3x + 4 which is 10 if x --> 1

So it looks like the limit is 1+2+3+4+5+...+n

2006-11-20 21:57:22 · answer #2 · answered by hayharbr 7 · 0 0

Let's do that.

For the first one:
1 + 2x + 3x^2 + 4x^3 + ... + nx^(n-1)

As x ---> 1

1 + 2 + 3 + 4 + ... + n

2006-11-20 21:57:27 · answer #3 · answered by ? 6 · 0 0

Do your own homework!!!

2006-11-20 21:55:37 · answer #4 · answered by Lil' Gay Monster 7 · 0 0

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