A beam of light in air strikes a piece of glass at an angle of 40 degrees. What is the index of refraction for the glass if the refracted angle is 25 degrees?
I know the answer is 1.52. I need to learn how to solve it and show the work in details. Please help me out. Thanks.
2006-11-20 13:44:44 · 3 answers · asked by eternal.diamonds 1 in Science & Mathematics ➔ Physics
use the formula sinA/sinB.
A is the angle of incidence,B is the angle of refraction.
so in this case it is sin40/sin25 = 1.52(to 3sig. fig)
2006-11-20 13:49:59 · answer #1 · answered by A 150 Days Of Flood 4 · 0⤊ 0⤋
The result is found using Snell's law of refraction:
If ø1 is incident angle and ø2 is refracted angle then
n1*sinø1 = n2*sinø2;
n1 are the indices of refration of the two materials. For air, n1 = 1,
so n2 = sinø1/sinø2
n2 = sin(40º)/sin(25º) = 1.52
2006-11-20 13:54:17 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
To traverse the thickness of the glass in vacuum, it takes: t = 6*E-2 m * cos (40 deg) / (2.99E-8 m / s) t = 1.537E-10 seconds It takes the SAME amount of time for light to traverse the thickness of the gass whether the light goes through vacuum or through glass (hence Snell's Law).
2016-05-22 03:37:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋