i have...
5x+10 + 7x-14 = -2x
12x-4 = -2x
14x = 4
x = 4/14
x = 2/17
right?
2006-11-20 13:15:22 · 15 answers · asked by sean_mchugh6 3 in Science & Mathematics ➔ Mathematics
5x + 10 + 7x - 14 = -2x
12x -4 = -2x
14x = 4
x = 4 / 14 = 2 / 7 (not 2/17)
2006-11-20 13:20:01 · answer #1 · answered by Anonymous · 0⤊ 0⤋
x = 2/7
2006-11-20 13:20:43 · answer #2 · answered by fenx 5 · 0⤊ 0⤋
x=2/7
2006-11-20 13:26:51 · answer #3 · answered by thephoneguy1234 4 · 0⤊ 0⤋
5(x + 2) + 7(x - 2) = -2x
5x + 10 + 7x - 14 = -2x
12x - 4 = -2x
14x = 4
x = (4/14)
x = (2/7)
So close, you just mistyped the denominator.
2006-11-20 15:40:12 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
Good until that last typo...
4/14 = 2/7
Btw, notice how many people said you were correct? What this shows is how the human mind sees patterns. We expect to see the 7 and just sort of subconciously ignore the 1. Sometimes it helps to check your work by going from bottom to top.
2006-11-20 13:20:57 · answer #5 · answered by modulo_function 7 · 2⤊ 0⤋
sean, you're right on, up to the last step that is, because when you reduce x = 4/14 to lowest common terms, you should be getting x = 2/7. I bet that was just a careless typing error, right?
2006-11-20 15:33:46 · answer #6 · answered by ronw 4 · 0⤊ 0⤋
x = 4/14 which is:
x = 2/7 in lowest terms.
(divide both numerator and denominator with 2 to get the lowest terms)
2006-11-20 13:23:23 · answer #7 · answered by pinky g 1 · 0⤊ 0⤋
x=2/7
4/14 is simplified to 2/7; all of your work is correct except that
2006-11-20 13:37:53 · answer #8 · answered by Mish 2 · 0⤊ 0⤋
x is equal to 2/7
2006-11-20 13:21:48 · answer #9 · answered by boomheadshot 2 · 0⤊ 0⤋
first subtract 2x from the two factors to assist get the variable on one section: 5x-3=2 then you definately might desire to attempt and isolate the variable by including 3 to the two factors: 5x=5 Then, as quickly as returned, in an attempt to isolate the variable you will possibly desire to divide the two factors by 5: x=a million
2016-10-04 04:47:07 · answer #10 · answered by lyon 4 · 0⤊ 0⤋