Quite an old example, and one of the best-known, is the so-called Pell equation X^2 - D.Y^2 = -1 or +1, where D is a square-free integer and X, Y are both to be integers. For example, when D = 3, there is no solution when -1 is on the right-hand side, but the solutions when it is +1 are (X, Y) = (2, 1), (7, 4), (26, 15), (97, 56), . . . an infinite series of integer pairs constructed by a simple rule starting from the first one (X' = 2X + 3Y, Y' = X + 2Y).
2006-11-21 04:32:14
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answer #1
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answered by Anonymous
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y = 1/x --> x = 1/y
For every value of x, there corresponds a number, y, which is its reciprocal. This implies that for every value of y, there also corresponds a value, x, which is its reciprocal. Since both number lines have an infinite number of elements, then both equations have an infinite number of elements in their solution sets.
2006-11-20 13:22:16
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answer #2
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answered by MathBioMajor 7
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If an equation in 2 variables is OK, then x-y = 1 will do fine.
2006-11-20 13:41:54
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answer #3
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answered by steiner1745 7
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3x/2 + 2y/3 = 25
2006-11-21 03:13:59
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answer #4
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answered by Akilesh - Internet Undertaker 7
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(x+1)/5 = (3x+3)/15
2006-11-20 13:03:37
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answer #5
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answered by hayharbr 7
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x = x
or
2x = 2x
2006-11-20 13:01:06
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answer #6
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answered by chris p 3
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x = [-infinity, +infinity]
2006-11-20 13:08:01
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answer #7
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answered by Jimie 1
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