Okay.. I need to multiply 7(2m - 6)
I have to get what m is first right??
do I multiply 7 by 2 and then 7 by 6... then I subtract 42 - 14 and.. what happened to M??
a little clarifying please?
2006-11-20 12:48:16 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
No. You DO NOT mix those numbers.
Its:
7*2m - 7*6
14m - 42 <---this is your answer
2006-11-20 12:53:18 · answer #1 · answered by bourqueno77 4 · 0⤊ 0⤋
Distributive law:
distribute the 7 over both terms in the ( )
so it becomes 7*2m - 7*6 = 14m - 42 ..
2006-11-20 20:54:19 · answer #2 · answered by modulo_function 7 · 1⤊ 0⤋
you cannot fully solve this problem unless the promblem is equal to something
all you need to do is distribute the 7 to the 2m and 6
so: 2m*7-6*7
and your answer is 14m-42
!@#$%^&*()_+you cannot do anything to it unless it is equal to something...
lets say it was equal to 0, then you could solve is:
14m-42=0
add 42 to each side
14m=+42
now divide each side by 14 to isolate m
m=42/14
so::: m=3
!@#$%^&*()+
2006-11-20 20:51:22 · answer #3 · answered by Mike P 3 · 0⤊ 0⤋
M???, but m equals 42 divided by 14 or m = 3
2006-11-20 21:02:36 · answer #4 · answered by Joe 1 · 0⤊ 1⤋
7 ( 2 m - 6 ) = 0
14 m - 42= 0
14 m = 42
m = 3
to me i think that is the answer.
2006-11-21 22:02:04 · answer #5 · answered by Angels Eyes 2 · 0⤊ 0⤋