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Can someone explain to me how to compute the following indefinite integral. (5x^9 + 4 sec(x)tan(x)) dx.

thank you!!

2006-11-20 12:29:54 · 2 answers · asked by wasatchjeeper 2 in Science & Mathematics Mathematics

2 answers

int(5x^9+4sec(x)tan(x))dx
=5(x^10)/10+4secx+C
=(x^10)/2+4secx+C

2006-11-20 12:32:47 · answer #1 · answered by Dupinder jeet kaur k 2 · 0 0

i'm going to apply INT extremely of the imperative sign. Now, INT dx/sqrt(4 - x^2) = (a million/2) dx/sqrt(a million- (x/2)^2) = arcsin(x/2) + C Given a = 0 and b = 2, subsequently imperative = arcsin(2/2) - arcsin(0/2) = pi/2

2016-10-04 04:44:58 · answer #2 · answered by lyon 4 · 0 0

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