Math Using Logs!?

Question

I need some help on this...

Suppose that y= (2 - log(100-x)) / 0.38 can be used to calculate the number of years "y" for "x" percent of a population of 936 sparrows to reach maturity. Approximate the percentage(to the nearest whole per cent) of sparrows that reached maturity after 1 year.

Answer 1

y = (2 - log(100-x)) / 0.38
1 = (2 - log(100-x)) / 0.38
0.38 = 2 - log(100-x)
-1.62 = -log(100-x)
1.62 = log(100-x)
e^1.62 = 100-x
2.718^1.62 = 100-x
5.05 = 100 - x
x = 94.95
x = 95% <---answer
936 * .95 = 889 sparrows reached maturity after 1 yr.