I have a bunch of physical science homework that I didnt do last semester so I have to do it now and I dont know any of the math portions so I could really use some help:
A hyraulic lift chair has its seat attached to a piston with an area of 11.2cm(2) yada yada yada the other piston exerts with an area of 4.12 cm(2) person on chair exerts downward force of 219 N what force needs to be exerted on the small piston to ;ift the seat.
7468 list on large piston, wit an area of 28.27cm(2), how much force must be exerted on small piston if it has an area of 1.325cm(2)?
2006-11-20 11:43:26 · 1 answers · asked by Anonymous in Education & Reference ➔ Homework Help
1.) The force over the area of the large piston will be equal to the force over the area of the small piston. (F1/A1 = F2/A2)
So:
F1 = 219N
A1 = 11.2 cm^2
F2 = x
A2 = 4.12 cm^2
219 / 11.2 = x / 4.12
x = 19.5536 * 4.12
x = 80.56 N
Armed with that, you should be able to do #2.
2006-11-21 01:50:35 · answer #1 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋