ok this is math homework.
how many 3- digit dumbers are there using 2,4,6,8, and 9?
2006-11-20 10:51:29 · 6 answers · asked by Haley 3 in Science & Mathematics ➔ Mathematics
125 because you have 5*5*5
2006-11-20 10:53:56 · answer #1 · answered by Jeff H 1 · 0⤊ 0⤋
30
2006-11-20 11:08:35 · answer #2 · answered by book_da_crook 1 · 0⤊ 0⤋
125
2006-11-20 10:59:24 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the answer is 60- 3 digit number combinations using these 5 numbers. without repeating the same number in any of the combinations... i hope this helped...
2006-11-20 11:12:19 · answer #4 · answered by heclee 3 · 0⤊ 0⤋
it is permutation without repetition with n = 5 , k = 3
total = n! / (n-k)! = 5! / 2! = 60 numbers
2006-11-20 10:58:30 · answer #5 · answered by James Chan 4 · 0⤊ 0⤋
i think 125
2006-11-20 10:58:44 · answer #6 · answered by ososweet92 2 · 0⤊ 0⤋