A canteloupe is rolled off the edge of a building roof with a velocity of 5.4m/s. It reaches the ground in 3 seconds. How high is the building? How far away from the base of the building does the canteloupe land? What happens to the canteloupe?
2006-11-20 10:38:09 · 2 answers · asked by Daniel 1 in Science & Mathematics ➔ Physics
First I am assuming that the roof is flat. This means that the canteloupe had a vertical velocity of 0 m/s when it started. (All the velocity is horizontal)
h = 1/2 a t^2
h = 0.5*9.8*3^2
h = 44.1 m high
v = x/t
5.4 = x/3
x = 16.2 m away from the building
The mellon splatters.
2006-11-20 10:46:12 · answer #1 · answered by Andy M 3 · 0⤊ 0⤋
I not sure, but, it kill whoever it hit in the head.
I hope this a subject that will enhance your career and benefit society. If, not, the school system, again, as many, has wasted your intellectual value.
2006-11-20 18:50:24 · answer #2 · answered by Snaglefritz 7 · 0⤊ 0⤋