3x^2 - 18x -27y^2 + 27
2006-11-20 10:15:33 · 4 answers · asked by h0m3r.simps0n 2 in Science & Mathematics ➔ Mathematics
3x^2 - 18x + 27 - 27y^2
3(x^2 - 6x + 9 - 9y^2)
3([x^2 - 6x + 9] - 9y^2)
3([(x-3)^2] - 9y^2)
3(([x - 3] + 3y)([x - 3] - 3y))
3(x + 3y - 3)( x - 3y - 3)
2006-11-20 10:22:55 · answer #1 · answered by Texas Cowgirl 3 · 0⤊ 0⤋
Sir:
3X^2 - 18X - 27Y^2 + 27 =
3X (X - 18) + 27 (1 + Y ) (1 - Y)
Hope that helps you,
Zah
2006-11-20 18:22:04 · answer #2 · answered by zahbudar 6 · 0⤊ 1⤋
3x² - 18x -27y² + 27
3x² - 18x + 27 - 27y²
3(x² - 6x + 9) - 27y²
3(x-3)² - 27y²
3 [ (x-3)² - 9y² ]
3 [ (x-3)² - (3y)² ] or 3(x-3)² - 3(3y)² <---answer
2006-11-20 18:22:19 · answer #3 · answered by bourqueno77 4 · 1⤊ 0⤋
3(x^2-6x+9-9y^2)=
3((x-3)^2-9y^2))=
3(x-3-3y)(x-3+3y)
2006-11-20 18:22:35 · answer #4 · answered by Greg G 5 · 0⤊ 0⤋