Hard Math question?

Question

In pentagon AMTYC, AC = MT = 10, YT = CY = 20, angle A = angle M = 135deg, and angle Y = 150deg. Find the area of the pentagon to the nearest square unit. Show your work please

Answer 1

▲CTY; CY² + YT² = CT²
▲CTY; 20² + 20² = CT²
▲CTY; 800 = CT²
▲CTY; 20√2 = CT
mid point CT = Z
ZT² + ZY² = YT²
[10√2]² + ZY² = 20²
200 + ZY² = 400
ZY² = 200
ZY = 10√2
▲CYT = 200√2 sq units

Trapezoid CAMT since
CA= 10, CT = 20√2, MT = 10
[from here you need a drawing but oh well, we'll do with what I can do here]

h= 5√2<--trust me on this one. Email me if you want and explanation.

V of trapezoid = h * b
V of t = 5√2 * base CT
V of t = 5√2 * 20√2
V of t = 200
200 [from trapezoid] + 200√2 [from ▲CYT] = 200(1 + √2)
= approx 482.8 sq units

Answer 2

a million+a million=2 apart from, somebody with far too lots time on their palms desperate to tutor it... "The evidence starts off from the Peano Postulates, which define the organic numbers N. N is the smallest set friendly those postulates: P1. a million is in N. P2. If x is in N, then its "successor" x' is in N. P3. there is not any x such that x' = a million. P4. If x isn't a million, then there's a y in N such that y' = x. P5. If S is a subset of N, a million is in S, and the implication (x in S => x' in S) holds, then S = N. then you certainly could define addition recursively: Def: enable a and b be in N. If b = a million, then define a + b = a' (utilising P1 and P2). If b isn't a million, then enable c' = b, with c in N (utilising P4), and define a + b = (a + c)'. then you certainly could define 2: Def: 2 = a million' 2 is in N by P1, P2, and the definition of two. Theorem: a million + a million = 2 evidence: Use the 1st area of the definition of + with a = b = a million. Then a million + a million = a million' = 2 Q.E.D. notice: there is yet another formula of the Peano Postulates which replaces a million with 0 in P1, P3, P4, and P5. then you certainly could substitute the definition of addition to this: Def: enable a and b be in N. If b = 0, then define a + b = a. If b isn't 0, then enable c' = b, with c in N, and define a + b = (a + c)'. you apart from might could define a million = 0', and a pair of = a million'. Then the evidence of the thought above is slightly different: evidence: Use the 2nd area of the definition of + first: a million + a million = (a million + 0)' Now use the 1st area of the definition of + on the sum in parentheses: a million + a million = (a million)' = a million' = 2 Q.E.D." Wow, he could be a actual hit with the girls...!! :)

Answer 3

split it into triangles in some smart way.

If you know one angle and sides of the triangle, you can compute it's area (0.5*side1*sin(angle)*side2). I bet you can also work out the other two angles. which should help with remaining triangles.

Answer 4

uh. you shouldn`t be putting your homework up here. teachers give you homework for YOU to do and YOU to find out. so it obviously wasn't a good idea huh?

Answer 5

easy but too much to put up here all work
good luck

Answer 6

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Answer 7

u put it in hw help duh