25x² - 20x = 1
that the probelm next step is
and somehow i am suppose to get
(_x - _)² = -1 right
but i can't factor that part out equally
2006-11-20 08:01:25 · 6 answers · asked by ijenjen3 2 in Science & Mathematics ➔ Mathematics
25x² - 20x = 1
25x² - 20x - 1 = 0
25x² - 20x - 1 + 5 = 0 + 5
25x² - 20x + 4 = 5
(5x - 2)² = 5
5x - 2 = +/- √5
5x = 2 +/- √5
x = (2 +/- √5) / 5
x = (2 + √5) / 5 and (2 - √5) / 5
2006-11-20 08:10:04 · answer #1 · answered by bourqueno77 4 · 1⤊ 0⤋
If you wanted it in that form, you would have:
25x^2 -20x -2 = -1
and you are right, they do not factor evenly.
To complete the square you would need to have:
25x^2 -20x + 4 = 5 (I added 4 to each side)
which factors to:
(5x -2)(5x - 2) = 5
(5x - 2)^2 = 5
2006-11-20 08:15:00 · answer #2 · answered by Andy M 3 · 0⤊ 0⤋
u can never get (_x - _)² = -1 bcoz square of anything cannot be negative.
2006-11-20 08:18:06 · answer #3 · answered by mane 5 · 0⤊ 0⤋
25x2-20x-1=0
delta=400+100=500
(20+sqr500)/50 and (20-sqr500)/50
2006-11-20 08:09:57 · answer #4 · answered by yuri Romanov 2 · 0⤊ 2⤋
25 x^2 - 20x=1
25x^2-20x-100+100=1
25x^2-20x-100=99
2006-11-20 08:08:04 · answer #5 · answered by reem h 2 · 0⤊ 1⤋
(5x)^2-2*5x*2+4=1+4
(5x-2)^2=(rt5)^2
2006-11-20 08:04:25 · answer #6 · answered by raj 7 · 0⤊ 1⤋