word probelm # 5?

Question

a restaurant owner wants to purchase some new tables, chairs and dinner plates for the dining area of her establisment. she plans to buy 4 chairs and 4 plates for each new table. she also needs 20 additional plates tokeep in case of breakage. if a table cost 100, a chair 50 and a plate 5 how many of each can she buy if she takes out a loan for 6500 to pay for the new items

Answer 1

Out of the $6500 loan, $100 is needed for the additional plates in case of breakage (20*$5 = $100).

This leaves us with $6400.

Let T = the cost of one table ($100)
Let C = the cost of one chair ($50)
Let P = the cost of one plate ($5)

The cost of one fully furnished table is:

T + 4*C + 4*P = 100 + 4*50 + 4*5 = 100 + 200 + 20 = $320

because the owner plans to purchase 4 chairs and 4 plates per table.

Now, divide the cost of one fully furnished table ($320) into our total amount of money to spend after the extra plates are purchased ($6400) to find the total number of fully furnished tables that can be purchased:

6400 / 320 = 20.

So, 20 fully furnished tables and 20 additional plates can be purchased with the $6500 loan.

The total number of tables is 20.
The total number of chairs is 20*4 = 80
The total number of plates is 20*4 + 20 = 100

I hope this helps!

Answer 2

n(100 + 4*50 + 4*5) + 20*5 = 6,500
n(100 + 200 + 20) + 100 = 6,500
320n = 6400
n = 20 tables
4n = 80 chairs
4n + 20 = 100 plates

Answer 3

let no. of tables be x
no. of chairs=4x
no.of plates=4x+20
100x+50*4x+5*4x
+5*20=6500
solve for x