I need help with this question:
1/(x-2) - 1/(x+3) = 1/10
2006-11-20 06:46:03 · 3 answers · asked by mr yass 2 in Science & Mathematics ➔ Mathematics
1/(x-2) - 1/(x+3) = 1/10
Multiply through by your LCD, 10(x - 2)(x + 3), giving
10(x + 3) - 10(x - 2) = (x - 2)(x + 3)
10x + 30 - 10x + 20 = x^2 + x - 6
x^2 + x - 56 = 0
Factor and solve for x
2006-11-20 07:00:40 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
1/(x-2) – 1/(x+3) = 1/10
Multiply both sides by 10(x+3)(x-2) and resolve
10(x+3) – 10(x-2) = (x+3)(x-2)
10x + 30 – 10 x + 20 = x^2 + x – 6
x^2 + x – 6 = 50
x^2 + x - 56 = 0
56 = 7 x 8
(x - 7)(x + 8) = 0
x = 7 or x = -8
2006-11-20 15:12:40 · answer #2 · answered by Mikey_T 3 · 0⤊ 0⤋
check my answer from before, it is corrct.
other people have had problems with double negatives i think. just to confirm thr answer is x=7 or x= minus8!!
full solution on the first question you asked!!
any probs get in touch
2006-11-20 15:09:36 · answer #3 · answered by Anonymous · 0⤊ 0⤋