Fractions in Quadratics problem?

Question

I need help with this question: (unable to put line under 1's)

1 - 1 = 1
(x-2) (x+3) 10

Answer 1

assume set-up
1/(x-2)-1/(x+3)=1/10
(x+3)-(x-2) =(x-2)(x+3)/10
50= x^2+x-6
x^2+x-56=0
(x+8)(x-7)=0

>>>> x= -8 or 7

i hope that this helps

Answer 2

The way to write this in Yahoo! is
1/(x-2) - 1/(x + 3) = 10

Always in equations with fractions you can get rid of fractions by multiplying each term by the lowest common denominator, in this case 10(x - 2)(x + 3).
When you do this, the x -2 on the bottom of the first term cancels with the x-2 in the multiplier, and gives 10(x+3).
The x+3 on the bottom of the second term cancels with the x+3 in the multiplier and gives 10(x-2).
On the right side the 10 on the bottom cancels with the 10 in the multiplier.

So you get
10(x+3) + 10(x-2) = (x-2)(x+3)
You can expand these and solve the resulting quadratic equation can you? If not I'm sure someone else has stolen your thunder by writing out the complete calculation for you by now!

Answer 3

Assume you mean

1/(x - 2) - 1/(x + 3) = 1/10

Clear the fractions by multiplying both sides by their LCD, which is

10(x - 2)(x + 3)

10(x + 3) - 10(x - 2) = (x - 2)(x + 3)
10x + 30 - 10x + 20 = x^2 + x - 6
50 = x^2 + x - 6
x^2 + x - 56 = 0
(x + 8)(x - 7) = 0
x = -8, 7

These roots check in the original equation

Answer 4

First do away with the fractions by utilising multiplying by utilising 15 3(x+3)+x+4=5 boost the bracket 3x+9+x+4=5 carry at the same time x-words on the left and numbers on the main astounding 4x=-8 Divide by utilising 4 to get x x=-8/4 = -2 So x=-2

Answer 5

is the question

1/(x-2) - 1/(x-3) = 1/10?

um then lcd = 10(x-2)(x-3)
state that X can not equal to -2 or -3

multiply each and cancel and you will get

10(x-3) - 10(x-2) = (x-2)(x-3)
10x - 30 - 10x + 20 = (x-2) (x-3)
20x - 10 = (x-2)(x-3)
20 x - 10 = x² - 5x + 6

bring everything over and combine like terms

x² - 5x - 20x +6 - 10

solve.

Answer 6

put over a common denominator of (x-2)(x+3)

it becomes

(x+3)-(X-2) all over (x-2)(x+3) = 1/10

multiply up by (x-2)(x+3) to get

(x+3)-(x-2) = (x-2)(x+3)/10

multiply up by 10

10( (x+3)-(x-2)) = (x-2)(x+3)

expand

10x + 30 -10x +20 = x squared +x -6 (watch the double negative)

collect like terms

x squared +x -56 = 0

factorise

(x+8)(x-7)=0

x= -8 or x= 7

Answer 7

Oh you have to click on the font key on your works or word then click on the Underscore key and it will put that line right under those 1's but you can't do it on yahoo.....

Answer 8

take lcm
(x+3-x+2)/(x-2) (x+3)
=1/10
cross multiply
10(2x+5)=(x-2)(x+3)
20x+50=x^2+x-6
x^2-19x-56=0
solve for x