3 digit # div by 3-my 10s digit is 3 times my hundreds digit-sum is 15-if digits reveresed div by 6 &3?

Answer 1

the number is 267

Answer 2

Let ABC be the 3-digit number.

10's digit is 3 times 100's digit. Therefore, B = 3A.

If digits are reversed, you get CBA which is
divisible by 6 and 3. If it is divisible by 6, then it
must be even. That is, A is even (= 0, 2, 4, 6, 8).

If A = 0, 2, 4, 6, 8, then B = 0, 6, 12, 18, 24.

But B is only a single digit, so B = 0 or 6.

But A and B can't be both zero, because the sum
of the digits is 15, and that would mean C = 15.

Therefore, B can only be 6 and so A must be 2.

6 + 2 = 8. Subtarct this from 15 to get C = 7.

ABC is therefore 267.