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6 answers

The answer is 393.

Start with 333.
It's an easy 3-digit number that is divisible by 3
Tens digit id 3 times more than hundreds.
So 393.
Does it add up to 15?
Yes it does!

:) :) :)

2006-11-20 06:30:09 · answer #1 · answered by ? 3 · 0 0

Let h= the hundred's digit
Let t = the ten's digit
Let u = the units
Then the number is 100h +10t +u
We are given that t=3h and h+t+u=15
If h=1 then t =3 so u= 11 which is impossible

If h=2 then t=6 so u =7 This would give 267 as the number but
it is not divisible by 3 and so must be rejected

So h=3 and t=9 must be correct because any larger value of h would produce too large a number for t.

Thus u = 15-12=3 and the final solution is 393

2006-11-20 14:37:01 · answer #2 · answered by ironduke8159 7 · 0 0

393

2006-11-20 14:22:32 · answer #3 · answered by frodobaggins115 4 · 0 0

393

2006-11-20 14:20:42 · answer #4 · answered by m.p. 2 · 0 0

393

2006-11-20 14:20:24 · answer #5 · answered by Babygirl 2 · 0 0

393

2006-11-20 14:20:05 · answer #6 · answered by sixcannonballs 5 · 0 0

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