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find the measure of an angle whose supplement is 2 times its complement.

supplement is 180
is <--> =
2 times = 2x
its complement =90?

is that what it means

if it is then that means

180 = 2x - 90? what there to solve? am i finding the supplement or a complement angle?

2006-11-20 06:16:18 · 4 answers · asked by blinded_by_you01 1 in Science & Mathematics Mathematics

4 answers

The only angle for which that would be true is 0 degrees
Proof:
x is the angle you're looking for
y is the compliment
z is the supplement

x+y=90
x+z=180
z=2y

then
x + 2y = 180
solve the compliment equation for y and substitute
x + y=90
y=90 - x

x + 2 (90-x) = 180
x + 180 - 2x = 180
-x = 0

2006-11-20 06:31:20 · answer #1 · answered by Anonymous · 0 0

I think that the supplement is what it takes to add to 180 deg
ditto complement ditto 90 deg

right?

So,

let a = the angle
supplement of a = 2 times complement of a means:

180-a = 2(90-a) right?

180-a = 180 -2a
0 = -a does that make sense? Yes, it does!

Two angles are called supplementary angles if the sum of their degree measurements equals 180 degrees. One of the supplementary angles is said to be the supplement of the other.

Two angles are called complementary angles if the sum of their degree measurements equals 90 degrees. One of the complementary angles is said to be the complement of the other.

2006-11-20 14:23:05 · answer #2 · answered by modulo_function 7 · 0 0

Let Θ = the angle you're looking for

The problem states that the supplement (i.e. 180 - Θ) is 2 times its complement (i.e. 2·(90 - Θ)). So set these two quantities equal to one another:

180 - Θ = 2·(90 - Θ)

(you ALMOST got it right; and you're finding the angle itself, not its complement or supplement)

And solve for Θ:

180 - Θ = 180 - 2Θ
Θ = 0 (not a very interesting result)

2006-11-20 14:26:12 · answer #3 · answered by Anonymous · 0 0

you're looking for the compliment I think, so I think you've already solved it. It's 90. I could be wrong though, so you may want to wait for a second opinion.

2006-11-20 14:20:53 · answer #4 · answered by frodobaggins115 4 · 0 0

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