y+3<0, sketch the graph of the solution?

Question

If I'm not mistaken (after changing it to y+3=0), I need to substitute 0 for y, which gives me 0+3=0, y=3. This is a dashed vertical line extending from (0,3) and shaded to the left of y=3. Am I correct?

Answer 1

This is equivalent to y < -3. Since y = -3 would be a HORIZONTAL (not vertical) line, you'd graph a dotted line going straight across at -3 on the y-axis. Since you want the y-values that are LESS than that, you'd shade below that line.

Answer 2

take x as the horizontal axis and y as the vertical axis

plot the grpah for y + 3 = 0
or y = -3
this is a straight line parallel to the x axis and at -3 units below the x axis.

as in the condition, y + 3 < 0 or y < -3


thus the portion below the line we drew is the required portion , and you can shade it as your answer.The line itself should be shaded as it is < and not ≤ and so any point on the line y -3 = 0 cant be part of the solution.

I hope this helps ,
Have a nice day

:)

Answer 3

The solution set is all values where Y is less than -3...This is an inequality. You cant make it into an equality that way.

Where on the graph do you find the Y axis is negative?

That's right... below the X axis. The solution set is defined by a line parallel to the X axis and including all values under the line
below Y=-3

Answer 4

Y at it's maximum value can be -4 since Y+3 must be lower than 0 which means Y must be negative so y= -4 to negative infinity

Answer 5

the answer is

y+3<0
-3 -3
y<-3
so why can be anything that is -3 or less then -3