A uniform solid disk with a mass of 32.3 kg and a radius of 0.264 m is free to rotate about a frictionless axl

Question

A uniform solid disk with a mass of 32.3 kg and a radius of 0.264 m is free to rotate about a frictionless axle. Forces of 90.0 N and 125 N are applied to the disk.
(a) What is the net torque produced by the two forces? (Assume counterclockwise is the positive direction.)

(b) What is the angular acceleration of the disk?

Assume counterclockwise is the positive direction

Answer 1

The moment of inertia of the disk is 0.5*m*r^2 (ref.). If the forces are applied tangentially at the rim and in the same rotational direction, the torque is r*F = r*(90+125) and the angular acceleration is torque/inertia = r*(90+125)/(0.5*m*r^2) = 2*(90+125)/(m*r). From the information given, there is no way to know if the forces are oriented to produce CW or CCW rotation. Are we maybe missing a picture?