What is the frequency of the oscillation of the mass "2m" ?
2006-11-20 02:51:13 · 5 answers · asked by sailordragonball 2 in Science & Mathematics ➔ Physics
Could someone please clearly explain the math portion?
2006-11-20 03:31:28 · update #1
f = (1/2pi)sqrt(k/m); where f = frequency of oscillation, m = mass, and k = spring coefficient
Thus f' = f [sqrt(k/2m)/sqrt(k/m)] = f sqrt(m/2m) = f sqrt(1/2); where f' is the frequency of the spring with 2m mass.
The physics lesson is that spring frequencies vary as the square root of the masses. [See source.]
2006-11-20 03:19:32 · answer #1 · answered by oldprof 7 · 0⤊ 0⤋
Since the period is square root (k/m) where k is the spring constant, m is the mass, if you double the mass, the period should change by the square root of 1/2.
2006-11-20 02:57:44 · answer #2 · answered by Gene 7 · 0⤊ 0⤋
period= k/ (m^1/2)
frequency is proprtioal to 1/period
so, new frequency= m^1/2 f
2006-11-20 03:13:58 · answer #3 · answered by kapilbansalagra 4 · 0⤊ 0⤋
Frequency of 2m is f/root2
2006-11-20 02:55:36 · answer #4 · answered by promy 1 · 1⤊ 0⤋
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2016-10-22 10:16:01 · answer #5 · answered by Anonymous · 0⤊ 0⤋