How do you know where the chiral centres are on a glucose molecule?

Answer 1

Any carbon atom which has 4 different groups bonded to it will be a chiral centre. There are 4 such atoms in the glucose molecule, though it can be hard to make that out when it's in a ring.

The links below may help.

Answer 2

a chiral centre is any carnbon atom which has four different side chains attached to it. if in a ring structure it has to be a single bonded structure and have different molecules. dont think it can possibly be in a ring but the ring structure can be a side chain. i know as am in 3rd yr chemistry course. an example is beta pyranose, rearrange the ring from a 6C ring to a 5C ring and the C that is out of the ring is the chiral centre.

Answer 3

Yeah, what Nam pronounced is right, yet once you check out your backside carbon, it particularly is written as CH2OH. i'm assuming you're in all probability responsive to what a chiral centre is; between the finest techniques of determining a chiral centre is that if there are 4 distinctive clever communities surrounding it. as quickly as there are 2 hydrogens, or a carbonyl team, you carbon centre isn't chiral. you have drawn a Fischer projection, and for my section i won't be in a position to stand them because of the fact sugars exist in a cyclic systems (the two pentose or hexose formations), with an alcohol from the 4th or 5th carbon condensing conveniently with the aldehyde. interior the cyclic pyranose formation, there are 5 chiral carbons, yet with furanose formation, there are 4 chiral carbons.

Answer 4

here's a bit of info:
http://www.soton.ac.uk/~orgchem/CHEM1002/Ch1002L3.pdf