2006-11-20 01:10:12 · 7 answers · asked by wicked 1 in Science & Mathematics ➔ Mathematics
change in x = 10-(-4) = 14
change in y = 0-0=0
total change = sqrt(14^2 + 0^2)
= sqrt 196
= 14
2006-11-20 01:12:46 · answer #1 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
It is so simple that the formula is not necessary. Since both of the points have Y values of 0, the answer is just the difference between the X values. If you picture it on a graph, it is just two points on the X axis, and you can immediately see the distance if 14.
2006-11-20 09:21:05 · answer #2 · answered by damo 2 · 0⤊ 0⤋
Distance formula
d = â(x₂- x₁)² + (y₂- y₁)²
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Ordered Pairs
(10. 0)(- 4, 0)
d = â[10 - (-4)] ² + ( 0 - 0 )²
d = â[ 10 + 4]² + (0)²
d = â[14]² + 0
d = â196
d = 14
The answer: The distance between (10, 0) and ( -4, 0) is 14.
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2006-11-20 10:10:34 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
Distance between two points (x1,y1) and (x2,y2) is
r = sqrt[(x1-x2)^2 + (x1-x2)^2]
Thus, for (10,0) and (-4, 0)
r = sqrt[(10-(-4))^2 + (0-0)^2]
= sqrt[(14)^2 + 0]
= sqrt[14^2]
= 14
Thats the answer
2006-11-20 09:15:25 · answer #4 · answered by Paritosh Vasava 3 · 0⤊ 0⤋
using de formula
{ (x 1 - x2 )2 + (y1 -y2)2 }^2
by this way ans s 14.
2006-11-20 09:24:36 · answer #5 · answered by navigator 1 · 0⤊ 0⤋
as both are on x axis distance is simply (10 - (-4)) =14unit
2006-11-20 09:19:09 · answer #6 · answered by Pramita 1 · 0⤊ 0⤋
plot it on the graph and 14 is the answer
2006-11-20 09:35:46 · answer #7 · answered by oee22 2 · 0⤊ 0⤋