______________ has real number solutions
2006-11-20 01:09:48 · 4 answers · asked by wicked 1 in Science & Mathematics ➔ Mathematics
The discriminant
√b² - 4ac portion of the quadratic Formula
x = - b ± √b² - 4ac/ 2a is negative , no real number solutions
- - - - - -s-
2006-11-20 02:16:33 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
No real solutions.
Since, there will be imaginary part with each solutions, the solutions will be complex numbers
2006-11-20 09:17:48 · answer #2 · answered by Paritosh Vasava 3 · 0⤊ 0⤋
it doesn't have real roots, but for certain purposes, an imaginary unit "i" is defined as the square root of "-1" and you can find "complex" roots for your equation. in this general case they will be [(-b - i * sqr(4 * a * c - b ^ 2)) / 2 * a] and [(-b + i * sqr(4 * a * c - b ^ 2)) / 2 * a]
2006-11-20 09:20:31 · answer #3 · answered by the_guy_with_the_thing 2 · 1⤊ 0⤋
the equation will not have any real solution, it have complex solution thatis in terms of imaginarty numbers (i=sqrt(-1))
2006-11-20 09:22:41 · answer #4 · answered by Pramita 1 · 0⤊ 0⤋