Solve the system?

Question

x + y = 4
-x + y = 2

Answer 1

x + y = 4- - - - - -Equation 1
-x + y = 2- - - - - Equation 2
- - - - - - -

2y = 6

2y/2 = 6/2

y = 3

The answr is y = 3

Insert the y value into equation 1

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Solving for x equation 1

x + y = 4

x + 3 = 4

x + 3 - 3 = 4 - 3

x = 1

The answer is x = 1

Insert the x value into equatiion 1

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Check for equation 1

x + y = 4

1 + 3 = 4

4 = 4

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Check for equation 2

- x + y = 2

- 1 + 3 = 2

2 = 2

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The solution set { 1, 3 }

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Answer 2

x+y= 4 ------- Equation 1
-x+y=2

=> 2y=6
=> y=6/2
=> y=3 Ans.

Now for 'x', put y=3 in equation 1:

x+y= 4
Therefore, By putting the value of 'y', we get:

x+3= 4
=> x= 4-3
=> x= 1 Ans.

FINAL ANSWERS: y= 3 and x=1.

Answer 3

x + y = 4 ....(1)
-x + y = 2...(2)

Adding both equation we get
(x+y)+(-x+y)= 4+2
=>x+y-x+y= 6
=>2y= 6
=>y= 6/2 = 3

Substituting y=3 in (1) we get
x+3=4
=>x=4-3 = 1
Thus solution is x=1, y=3

Verification:
eq (1) x+y = 1+3=4
eq (2)-x+y = -1+3=2

Answer 4

x+y=4
so y= 4-x
putting the value of y in other equation
-x+(4-x)=2
-x+4-x=2
4-2x=2
4-2=2x
2x=2
x=1
putting this value in any equation let it be first
1+y=4
y=3

verification
x=1
y=3
x+y=4
lhs
x+y=1+3
=4
=rhs
hence verified for first equation
taking second equation
lhs=-x+y
=-1+3
=2
hence also verified