For the function y=x^2-4x-5, perform the following tasks: Put the function in the form y=a(x-h)^2+k?

Answer 1

Since the cofactor of x^2 is 1, then a is 1
Now take half of -4x to get h (that's 2x) and compute
(x-2)^2 = x^2-4x +4 So add -9 t0 it all so
we have x^2-4x +4 -9 = x^2-4x -5 and finally

y=(x-2)^2-9

Answer 2

y=x^2-4x-5
=>y+5=(x^2-4x) + (4 - 4)
=>y+5= x^2 - 4x +4 - 4 [add and subtract 4 from RHS]
=>y+5= (x - 2)^2 - 4
=>y= (x - 2)^2 - 4 -5
=>y= (x - 2)^2 - 9
Which is in y=a(x-h)^2+k form, with a = 1, h = 2, k = -9

Answer 3

1)divide the "4" by 2 and then square the result ANS=4
2) Add, 4 and also subtract 4 y = (x^2 -4x +4) -4 -5
3) factorise y= (x-2)^2 -4-5
4) simplify everythin y=(x-2)^2 -9

so a =1
h=2
k=-9

Answer 4

y = x^2-4x - 5
= x^2 -2(x)2 + 2^2 - 2^2 -5
= (x-2)^2 +(-9)

a= 1 h = 2 k = 9

Answer 5

2) For the function y = x^2 - 4x - 5, carry out here projects: a) positioned the function interior the form y = a(x - h)^2 + ok. answer: y=x^2-4x-5 =x^2-4x+4-4-5 =x^2-4x+4-9 =(x-2)^2-9 b) what's the equation for the line of symmetry for the graph of this function? answer: x=2 c) Graph the function utilising the equation partly a. clarify why it extremely is no longer mandatory to devise factors to graph while utilising y = a (x – h)2 + ok. instruct graph right here. rationalization of graphing. d) on your very own words, describe how this graph compares to the graph of y = x2? comparable shape moved interior the airplane. .

Answer 6

y = x^2-4x-5

y= (x^2-2.2x+4)-4-5 = ( x^2-2.2x+2^2)-9 = (x-2)^2-9

Here a=1, h=2, k=-9

Answer 7

y=(x^2-4x+4)-4-5
y=(x-2)^2-9