How do you calculate the question:
A drunken driver has a 10% chance of being stopped by the police resulting in the cancellation of his license. What is the probability that a person still has their license after driving intoxicated six times.
2006-11-18 23:34:11 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Since the probability of being stopped is 10%,
the probability of not being stopped is 90%.
The probability that this person has not been
stopped 6 times is (.9)^6=.53
53%
2006-11-18 23:40:18 · answer #1 · answered by albert 5 · 0⤊ 1⤋
p(drunken driver not being caught) = 9/10
p(drunken driver not being caught after 6 times)=(9/10)^6
=531441/1000000
2006-11-18 23:40:06 · answer #2 · answered by Oz 4 · 0⤊ 1⤋
The probability that a drunk driver is NOT pulled over is 90%.
The probability that a drunk driver is not pulled over in two 'chances' is 90% of 90% = 0.9*0.9 = 81%.
The probability that they get away with it six times is 0.9*0.9*0.9*0.9*0.9*0.9 = 0.9^6 = 0.531441 or roughly 53.1%
Good luck with the assignment.
2006-11-18 23:41:10 · answer #3 · answered by leapyearer 2 · 0⤊ 1⤋
0.9^6=0.53 or 53%
2006-11-18 23:39:22 · answer #4 · answered by epbr123 5 · 0⤊ 1⤋
zero
2006-11-18 23:50:41 · answer #5 · answered by Anonymous · 0⤊ 2⤋