In a city where 30% occupants are foreign, the probability of a foreign being questioned is 40%, while for a local is 10%. What is the likelihood that any person chosen at random will be questioned.
2006-11-18 22:20:27 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
0.30 * 0.40 + 0.70 * 0.10
= 0.12 + 0.07 = 0.19
= 19%
2006-11-18 22:36:05 · answer #1 · answered by z_o_r_r_o 6 · 1⤊ 0⤋
_RB_RB_RB_R_ The blanks can incorporate 0 or greater blue marbles, however the 1st and final blanks won't be able to the two be empty. style of suggestions on a thank you to distribute 5 marbles into 5 boxes (empty allowed) is C(5+5-a million, 5) the place C(n,ok) is binomial coefficient, and subtract out C(3+5-a million, 5) so risk is ( C(9,5) - C(7,5) ) / C(12,4) = 7/33.
2016-12-30 15:17:30 · answer #2 · answered by nourse 3 · 0⤊ 0⤋
Propability is of no consequence to anything. If you are going by propability, you have to factor in their ages, their habits, their history, where they go, where they've been, where you are when you ask them, why they are there, what would have changed their routine that day, and an incalculable amount of other possibilities. You cannot apply propability to humans at large. now if it was one person, that might be interesting.
2006-11-18 22:24:55 · answer #3 · answered by Anonymous · 0⤊ 0⤋
you have only mentioned half the question (what about the remaining 50%, anyways the answer (I guess) is 0.24 for foreigners while for locals is 0.14 and the remaining 0.62 would never be questioned(Ha..HaHa....Ha)
2006-11-18 22:35:21 · answer #4 · answered by So_Hot_An_Ice 2 · 1⤊ 0⤋