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In February of the year 2000, my brother Ethan was eleven times as old as my cousin Chloe. In February of 2012, he will be three times as old as my cousin. How old was my cousin in February of 2000?

2006-11-18 17:08:42 · 9 answers · asked by MarkAngelo 2 in Science & Mathematics Mathematics

9 answers

Let x = age of Chloe in 2000 and y = age of Ethan in 2000, then
y = 11x and
y+12 = 3(x+12)
Replace y with 11x in the second equation
11x + 12 = 3(x+12)
11x + 12 = 3x + 36
8x = 24
x = 3

2006-11-18 17:17:06 · answer #1 · answered by MsMath 7 · 4 2

3

2006-11-18 17:23:54 · answer #2 · answered by Angel Girl 5 · 2 1

3

2006-11-18 17:12:00 · answer #3 · answered by Stretchy McSlapNuts 3 · 3 1

Let Chloe = 'y'
Ethan = 'x'
x = 11y
x + 12 = 3(y + 12)
But x = 11y
Therefore,
11y + 12 = 3(y + 12)
11y + 12 = 3y + 36
11y = 3y + 36 - 12
11y = 3y + 24
11y - 3y = 24
8y = 24
y = 24/8
y = 3
You cousin was 3 years old in Feb. 2000

2006-11-18 19:29:46 · answer #4 · answered by Akilesh - Internet Undertaker 7 · 1 0

let x be chloe's age on the year 2000
so ethan age at that time will be 11x

at 2012,
chloe will be x+12 years old
and ethan will be 11x+12 years old

so the equation will be:

3(x+12) = 11x+12

find x

3x+36=11x+12
3x-11x=12-36
-8x=-24
x=3

chloe was 3 years old in feb of 2000.

2006-11-18 19:48:53 · answer #5 · answered by fii 3 · 1 0

ok i'm not sure if this is right or wrong. i did the problem in a couple of minutes.

11c = E
3(12+c) = 12+E

3(12+c) = 12+E
24+3c = E

11c = E
24+3c = E

11c = 24+3c
8c = 24
c = 3

11(3) = E
33 = E

Chloe was 3 years old in February of 2000 and Ethan was 33 in February of 2000.

2006-11-18 17:35:44 · answer #6 · answered by checkmarks2177 2 · 1 2

in 2000 e=11c
in 2012 e+12=3(c+12)
substitute
11c+12=3(c+12)
11c+12=3c+36
8c=24
c=3 She was 3 in 2000.

2006-11-18 17:34:14 · answer #7 · answered by yupchagee 7 · 2 1

E = 11*C
E+12 = 3(C+12)

SOLVING E+12 = 3C+36 OR E -3C = 24
SUBSTITUTING 11C-3C=24

OR 8C=24
OR C=3
(evelyn was 33 but thats not the question)

2006-11-18 17:20:01 · answer #8 · answered by spoonish18 2 · 1 1

duh 3... do u want me to explain it further??

2006-11-18 22:02:10 · answer #9 · answered by gonpatrick21 3 · 1 1

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