hi all,
If the average amount of rainfall is 90mm per month, but one year 123mm falls, calculate the monthly percent increase from the normal rainfall. What is the equation that I should use?
2006-11-18 16:36:50 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sorry, yes I did mean it was a monthly amount
2006-11-18 16:47:39 · update #1
Thanks Dupinder, I think your answer is what I am looking for. :)
2006-11-18 16:48:51 · update #2
90 + 123 = 213 divide by 2 = 106.5 mm
106.5 - 90 = 16.5% increase from the normal rainfall
2006-11-18 16:40:58 · answer #1 · answered by Dawn J 4 · 0⤊ 1⤋
You might want to restate your question. You mention average monthly rainfall of 90mm and then state that in one YEAR 123mm fall. Do you mean in one MONTH 123mm fall? If that is your question you are looking for a percent increase/decrease formula. Here's the best one I know: Find the difference between the old and new values (the absolute value), then divide that difference by the OLD (original) value, then multiply the answer by 100.......the answer is the percentage increase or decrease [depending on whether the new value is greater or lesser than the old (original) value].
Simply stated: Find the absolute value of the difference between the two values in question, then divide that absolute value by the ORIGINAL value, then multiply that answer by 100 [move the decimal point (2) spaces to the right]......the answer is the percent increase or decrease of the two original values.
Your problem: 123-90=33 or 90-123=-33, either way the absolute value is 33.
Then 33 divided by 90 = .3666666........
.3666 multiplied by 100 equals 36.66 %. (increase, in this case).
2006-11-18 17:15:28 · answer #2 · answered by popcorn 3 · 0⤊ 0⤋
ok, shall we are saying she paid 'x' for the computer. She bought the computer for a income of 25%. or, x + 25% of x = 60 or, x + (25/100)* x = 60 or, x + (a million/4) * x = 60 or, x (a million + a million/4) = 60 or, x (5/4) = 60 or, x = 60 * 4 / 5 for this reason, x = 40 8 So, Chrissie paid £40 8 for the computer! :)
2016-11-29 06:37:07 · answer #3 · answered by gnegy 4 · 0⤊ 0⤋
Isn't there an error in your question? You state that in one year 123 mm of rain falls. Did you mean in one month 123 mm of rain falls?
2006-11-18 16:45:09 · answer #4 · answered by davidepeden 5 · 0⤊ 0⤋
123-90=33
(33/90)*100=110/3=36.67%
2006-11-18 22:43:42 · answer #5 · answered by alaa_cancer 3 · 0⤊ 0⤋
123/90=1.366...
or a 36.67% increase over the average.
2006-11-18 17:35:43 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋
123/90 = 1.367
1.367 x 100% = 136.7%
Which would mean 36.7% above normal, since normal would be considered 100%.
--Ron
2006-11-19 03:44:03 · answer #7 · answered by aspencrest 1 · 0⤊ 0⤋
[(123-90)/90]*100
(33/90)*100
110/3
36.67%
2006-11-18 16:39:20 · answer #8 · answered by Dupinder jeet kaur k 2 · 0⤊ 0⤋