A man pushes a 2kg broom at a constant speed across the floor. the broom handle makes a 50 degree angle with the floor he pushes the broom with a 5.0 N force.
I can find the x direction forces but I'm having trouble finding the y direction, can anyone show me how to find the y forces?
2006-11-18 15:39:51 · 4 answers · asked by w_xsoadx_w 2 in Science & Mathematics ➔ Mathematics
Let's see if I can remember the basics. F = ma, so the vertical force exerted by the weight of the broom ought to be 2 kg • 9.8 m/s² = 19.8 N (if N = kg • m / s²). Add to that the vector component of the 5 N force at 50°, F = 5 sin 50°.
2006-11-18 15:56:21 · answer #1 · answered by Philo 7 · 0⤊ 0⤋
Doesn't look like the beginning of the problem is really needed to solve this problem. The equation for force is F = ma where m is mass, and a is acceleration. So, the normal force would be simply m times a which is: 52.1kg * 27.4 m/s/s = 1427.54 Newtons
2016-03-29 01:10:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I expect you found the horizontal force (ignoring friction!) is
5.0*cos(50 deg)
The downward component of his push is
5.0*sin(50 deg), and the weight of the broom,
i.e. 2g N (about 19.6 N)
has to be added to this. And that's the y component.
2006-11-18 15:47:04 · answer #3 · answered by Hynton C 3 · 0⤊ 0⤋
Fx = 5 cos50° ≈ 3.2N
Fy = 5 sin50° + 2g ≈ 23.4N
2006-11-18 15:44:11 · answer #4 · answered by Wal C 6 · 0⤊ 0⤋